Los Medanos Elementary

Observer

     I saw a lot of teams rushing to set up before the fair started in order to have everything ready for the children to try their experiments. I also observed groups setting up during because they had to re-do the experiment for more children to test what they had. I saw the cooperation between team members as all were struggling together to let re-setup their tables. My teams' table was very messy because the solution that was created got all over the place and my team members all got cornstarch on ourselves.

Participants

     The children were smiling and talking to everyone around them saying how they liked it and even some of the parents tried it. A lot of the participants wanted to take the sololsquid home.

Responses

     The children were really engaged into creating the product. They said that they thought it was fun and it looked really cool. I think this night really helped them understand how awesome and interesting science can be because all they did was mix a few simple things to see the affect it creates.

Take Away

     Through this experience I had to cooperate with others in order to have our experience be successful. I would have wanted to be more prepared

H - Weezy Problem

q ^2	(given) .41
q	.64
p	.36
p ^2	.13
2pq	(2)(.36)(.64) = .46

p^2 + 2pq + q^2	(.13) + (.46) + (.41) = 1
# of homo dominant	q^2 = .41 = 41% (q^2 x 1000) = (.41 x 1000) = 410
# of homo recessive	p^2 = .13 = 13% (p^2 x 1000 = (.13 x 1000) = 130
# of heterozygous	2pq = .46 = 46% (2pq x 1000) = (.46 x 1000) = 460

            We are given the value q^2 (homozygous dominant) of .41 and an initial population of 1000 individuals. 

Step 1: Find q by taking the square root of q^2 which equals .64

Step 2: Find p by knowing q + p = 1, therefore 1 - .64 = .36

Step 3: Find p^2 by taking p and squaring it, or multiplying it by itself. .36 x .36 = .13

Step 4: Find 2pq by plugging in the values p and q. (2)(.36)(.64) = .46

After finding all values, I then found the # of homo dom. individuals, # of homo rec. individuals, and # of heterozygotes in the population. 

In order to do so, I multiplied the value of q^2 (.41) ,which also equals 41% of the population, by the total population (1000) and got 410 individuals.

The number of individuals that contain the homozygous recessive alleles are 13% of the population which is 130 individuals, which is found by multiplying p^2 by the total population as well.

Lastly, the number of heterozygous individuals takes up 46% of the population which is 460 individuals. This is found by multiplying 2pq by 1000, the total population as well.

Worm Lab

Solution A has the depressant. Solution B has the stimulant. Solution C is normal

According to the data my group and I have collected, the results were very obvious. For solution A, the pulse rates we collected were 19, 16, 12, 16, and 17 per minute. For solution B, the pulse rates resulted in 35, 28, 30, 29, and 31 per minute. Lastly in solution C, the rates per minute collected were 18, 25, 25, 20, and 19. A method I used for analyzing the data would be finding the averages of every solution. The average for solution A was 16, B was 25.2, and C was 21.4. The lowest average was solution A, therefore leading to the conclusion that it contained the depressant. Whereas solution B had the highest average creating the assumption that it contained the stimulant. Lastly, leaving C to being the middle number, which meant that it was normal.

This is a picture of the California Blackworms that were observed in this lab.

This a a picture of the worms through the microscope.